Question

Giải phương trình \(P\left( x \right) = 0.\)

Answer 1

\(\begin{array}{l}P\left( x \right) = 0\\\left( {x + 1} \right)\left( {3x - 1} \right) = 0\\TH1:x + 1 = 0\\x =  - 1\\TH2:3x - 1 = 0\\x = \frac{1}{3}\end{array}\)

Vậy \(x \in \left\{ { - 1;\frac{1}{3}} \right\}\)