\(\Leftrightarrow\frac{\left(x+1\right)\left(x^2-x+1\right)-\left(x-1\right)\left(x^2+x+1\right)}{\left(x^2-x+1\right)\left(x^2+x+1\right)}=\frac{3}{x^5+x^3+1}\)
\(\Leftrightarrow\frac{x^3+1-x^3+1}{\left(x^2+1\right)^2-x^2}=\frac{3}{x^5+x^3+x}\)
\(\Leftrightarrow\frac{2}{x^4+2x^3-x^2+1}=\frac{3}{x^5+x^3+x}\)
\(\Leftrightarrow2x^5+2x^3+2x=3x^4+6x^3-3x^2+3\)
\(\Leftrightarrow2x^5-3x^4-4x^3+3x^2+2x-3=0\)
26 ,giải phương trình.
a,\(\frac{1}{x-1}+\frac{2}{x^2+x+1}=\frac{3x^2}{x^3-1}\)
b,\(\frac{x}{2\left(x-3\right)}+\frac{x}{2\left(x+1\right)}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
c,\(\frac{x-1}{x+2}+\frac{x-2}{x+1}=\frac{2\left(x^2+2\right)}{x^2-4}\)
d,\(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
Giải phương trình:
a, \(\frac{2}{\left(1-3x\right)\left(3x+11\right)}=\frac{1}{9x^2-6x+1}-\frac{3}{\left(3x+11\right)^2}\)
b,\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^1-x+1}=\frac{3}{x\left(x^4+x^2+1\right)}\)
Giải phương trình:
\(\left(\frac{x+1}{x-2}\right)^2+\frac{x+1}{x-4}-3\left(\frac{2x-4}{x-4}\right)^2=0\)
Giải các phương trình sau:
a/ \(\frac{14}{3x-2}-\frac{2+x}{x-4}=\frac{3}{8-2x}-\frac{5}{6}\)
b/ \(\left(1-\frac{x-1}{x+1}\right)\left(x+2\right)=\frac{x+1}{x-1}+\frac{x-1}{x+1}\)
help meeeeeee!!!!!!
giải phương trình :
a) 3x(x-1)=(x-1)(x+2)
b) \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
c) \(\frac{1}{2}\left(x+1\right)+\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+2\right)\)
d) ** \(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\) ưu tiên câu d nha
Giải phương trình:
a,\(\frac{1}{3-x}-\frac{1}{x+1}=\frac{x}{x-3}-\frac{\left(x-1\right)^2}{x^2-2x-3}\)
b,\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
Giải phương trình sau
a) \(\frac{3}{2\left(x+1\right)}-\frac{x-2}{9}=\frac{2x+1}{18}\)
b) \(\frac{2x}{\left(x+1\right)\left(x-2\right)}+\frac{-2}{x-1}=\frac{1}{x+2}\)
Giái phương trình :
a,\(\frac{6x+1}{x^2-7x+10}+\frac{5}{x-2}=\frac{3}{x-5}\)
b,\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
c,\(\frac{1}{3-x}-\frac{1}{x+1}=\frac{x}{x-3}-\frac{\left(x-1\right)^2}{x^2-2x-3}\)
d,\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
1) Giải các pt chứa ẩn ở mẫu:
a)\(\frac{x}{2\left(x-3\right)}+\frac{x}{2x+2}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
b) \(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{4}{x^2-1}\)
c)\(\frac{1}{x-2}+3=\frac{x-3}{2-x}\)
