Question

Giải phương trình :

(-4x+1)(3x-7)=0

(2-3x)(x+4)=0

Answer 1

Giải:

a) \(\left(-4x+1\right)\left(3x-7\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}-4x+1=0\\3x-7=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=\dfrac{7}{3}\end{matrix}\right.\)

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b) \(\left(2-3x\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2-3x=0\\x+4=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-4\end{matrix}\right.\)

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