Giải hpt: \(\left\{{}\begin{matrix}\sqrt{x}+\sqrt{y}=2\\\sqrt{x+3}+\sqrt{y+3}=4\end{matrix}\right.\)
giải hpt: \(\left\{{}\begin{matrix}\sqrt{xy+\left(x-y\right)\left(\sqrt{xy}-2\right)}+\sqrt{x}=y+\sqrt{y}\\\left(x+1\right)\left(y+\sqrt{xy}+x-x^2\right)=4\end{matrix}\right.\)
Giải HPT:
1. \(\left\{{}\begin{matrix}x^2+y^2+\dfrac{2xy}{x+y}=1\\\sqrt{x+y}=x^2-y\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}\dfrac{1}{\sqrt{x+2}}+\dfrac{1}{\sqrt{y-1}}=\dfrac{2}{\sqrt{x+y}}\\x^2+y^2+4xy-4x+2y-5=0\end{matrix}\right.\)
Giải hpt \(\left\{{}\begin{matrix}\sqrt{y+3x}+\sqrt{2x+7y}=\sqrt{5x-y}+3\sqrt{x}\\x-4-\sqrt{y-2}=\sqrt{x^3-10x^2+33x-34}-\sqrt{y^3-9y^2+24y-16}\end{matrix}\right.\)
giải hpt
\(\left\{{}\begin{matrix}\sqrt{x}\left(\sqrt{x+3}+\sqrt{x}\right)=3\\\sqrt{x}+\sqrt{y}=x+1\end{matrix}\right.\)
1.Giải hpt bằng pp thêm bớt hằng số để nhân liên hợp
a,\(\left\{{}\begin{matrix}\sqrt{x^2-x-y}=\dfrac{y}{\sqrt[3]{x-y}}\\2\left(x^2+y^2\right)-3\sqrt{2x-1}=11\end{matrix}\right.\)
giai hpt
\(\left\{{}\begin{matrix}\sqrt{y}\left(\sqrt{x+3}+\sqrt{x}\right)=3\\\sqrt{x}+\sqrt{y}=x+1\end{matrix}\right.\)
giải giúp mik bt này vs mn!
1)\(\left\{{}\begin{matrix}2x^2+y^2+x=3\left(xy+1\right)+2y\\\dfrac{2}{3+\sqrt{2x-y}}+\dfrac{2}{3+\sqrt{4-5x}}=\dfrac{9}{2x-y+9}\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}\left(x+3y+1\right)\sqrt{2xy+2y}=y\left(3x+4y+3\right)\\\left(\sqrt{x+3}-\sqrt{2y-2}\right)\left(x-3+\sqrt{x^2+x+2y-4}\right)=4\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x-\dfrac{1}{x}=y-\dfrac{1}{y}\\2y=x^3+1\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}\sqrt{2x-3}=\left(y^2+2011\right)\left(5-y\right)+\sqrt{y}\\y\left(y-x+2\right)=3x+3\end{matrix}\right.\)
5)\(\left\{{}\begin{matrix}x^3+2x^2=x^2y+2xy\\2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14=x-2}\end{matrix}\right.\)
Giải hệ
a) \(\left\{{}\begin{matrix}x^2\left(y^2+1\right)+2y\left(x^2+x+1\right)=3\\\left(x^2+x\right)\left(y^2+y\right)=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\left(6x+5\right)\sqrt{2x+1}-2y-3y^3=0\\y+\sqrt{x}=\sqrt{2x^2+4x-23}\end{matrix}\right.\)
Giải bất pt
\(\dfrac{9}{\left|x-5\right|-3}\ge\left|x-2\right|\)
giúp mik giải bài hệ pt vs ạ!
1,\(\left\{{}\begin{matrix}x^2+y^2+\dfrac{2xy}{x+y}=1\\\sqrt{x+y}=x^2-y\end{matrix}\right.\)
2,\(\left\{{}\begin{matrix}2x^3+xy^2+x=y^3+4x^2y+2y\\\sqrt{4x^2+x+6}-5\sqrt{1+2y}=1-4y\end{matrix}\right.\)
3,\(\left\{{}\begin{matrix}2x^2+\sqrt{2}x=\left(x+y\right)y+\sqrt{x+y}\\\sqrt{x-1}+xy=\sqrt{y^2+21}\end{matrix}\right.\)
4,\(\left\{{}\begin{matrix}\sqrt{9y^2+\left(2y+3\right)\left(y-x\right)}+4\sqrt{xy}=7x\\\left(2y-1\right)\sqrt{1+x}+\left(2y+1\right)\sqrt{1-x}=2y\end{matrix}\right.\)