ta có:\(\dfrac{x-y}{z-y}\)=\(\dfrac{x-z+z-y}{z-y} \)=\(\dfrac{x-z}{z-y}\)+1=-10.
\(\Rightarrow\)\(\dfrac{x-z}{z-y} \)= -10 - 1= -11 \(\Rightarrow \) \(\dfrac{x-z}{z-y}\)= -11.
\(\Rightarrow\)-\((\dfrac{x-z}{z-y})\)=11 \(\Rightarrow\) \(\dfrac{x-z}{y-z}\)= 11.
Vậy kết quả là 11.
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