ĐKXĐ:...
\(\frac{1}{x}+\frac{1}{y+1}=1\Leftrightarrow x+y+1=xy+x\)\(\Rightarrow xy=y+1\)
Thay lên pt trên ta được: \(2x+3y=y+1+5\)
\(\Leftrightarrow2x+2y=6\Rightarrow x+y=3\Rightarrow x=3-y\)
\(\Rightarrow\left(3-y\right)y=y+1\Leftrightarrow y^2-2y+1=0\)
\(\Rightarrow y=1\Rightarrow x=2\)