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\(\left[\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{x-1}+\dfrac{\sqrt{x}\left(\sqrt{x}-1\right)}{x-1}\right]:\dfrac{2\sqrt{3x}}{x-1}\)
\(=\left(\dfrac{x+\sqrt{x}+x-\sqrt{x}}{x-1}\right).\dfrac{x-1}{2\sqrt{3x}}\)
\(=\dfrac{2x}{x-1}.\dfrac{x-1}{2\sqrt{3x}}=\dfrac{\sqrt{x}}{\sqrt{3}}=\dfrac{\sqrt{3x}}{3}\)
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