\(a\)) \(\sqrt{2}x-\sqrt{50}=0\)
\(\Leftrightarrow\sqrt{2}x-\sqrt{25}.\sqrt{2}=0\)
\(\Leftrightarrow\sqrt{2}x-\sqrt{5^2}.\sqrt{2}=0\)
\(\Leftrightarrow\sqrt{2}x-5\sqrt{2}=0\)
\(\Leftrightarrow\sqrt{2}\left(x-5\right)=0\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
\(b\)) \(\sqrt{3}x+\sqrt{3}=\sqrt{12}+\sqrt{27}\)
\(\Leftrightarrow\sqrt{3}x+\sqrt{3}=\sqrt{4}.\sqrt{3}+\sqrt{9}.\sqrt{3}\)
\(\Leftrightarrow\sqrt{3}x=\sqrt{4}.\sqrt{3}+\sqrt{9}.\sqrt{3}-\sqrt{3}\)
\(\Leftrightarrow\sqrt{3}x=\sqrt{2^2}.\sqrt{3}+\sqrt{3^2}.\sqrt{3}-\sqrt{3}\)
\(\Leftrightarrow\sqrt{3}x=2\sqrt{3}+3\sqrt{3}-\sqrt{3}\)
\(\Leftrightarrow\sqrt{3}x=4\sqrt{3}\Rightarrow x=4\)
Vậy \(x=4\)
a) √2x - √50 =0
=>√2x=5√2
=>x=5
b) √3x+√3=√12+√27
=>√3(x+1)=√3(2+3)
=> x+1=5
=>x=4
a. \(\sqrt{2}.x-\sqrt{50}=0\)
\(\rightarrow\sqrt{2}.x-5\sqrt{2}=0\)
\(\rightarrow\sqrt{2}.x=5\sqrt{2}\)
\(\rightarrow x=\frac{5\sqrt{2}}{\sqrt{2}}=5\)
Vậy nghiệm của phương trình \(x=5\)
b. \(\sqrt{3}.x+\sqrt{3}=\sqrt{12}+\sqrt{27}\)
\(\rightarrow\sqrt{3}.x+\sqrt{3}=2\sqrt{3}+3\sqrt{3}\)
\(\rightarrow\sqrt{3}.x=-\sqrt{3}+2\sqrt{3}+3\sqrt{3}\)
\(\rightarrow\sqrt{3}.x=4\sqrt{3}\)
\(\rightarrow x=\frac{4\sqrt{3}}{\sqrt{3}}=4\)
Vậy nghiệm của phương trình \(x=4\)
