\(\left(2^{160}-1\right)\cdot\left(15^2+7^3\right)=\left(2^{4\cdot40}-1\right)\cdot\left[\left(...5\right)+\left(...3\right)\right]\)
\(=\left[\left(...6\right)-1\right]\cdot\left(...8\right)\)
\(=\left(...5\right)\cdot\left(...8\right)\)
\(=\left(...0\right)\)
Vậy \(\left(2^{160}-1\right)\left(15^2+7^3\right)\) có chữ số tận cùng là 0