Question

Ggiúp mik nha

Answer 1

Ta có: a//b

nên \(\widehat{E_1}+\widehat{F_1}=180^0\)

mà \(\widehat{E_1}-\widehat{F_1}=30^0\)

nên \(\left\{{}\begin{matrix}\widehat{E_1}=\dfrac{180^0+30^0}{2}=105^0\\\widehat{F_1}=180^0-105^0=75^0\end{matrix}\right.\)

Vì a//b

nên \(\left\{{}\begin{matrix}\widehat{F_2}=\widehat{E_1}=105^0\\\widehat{E_2}=\widehat{F_1}=75^0\end{matrix}\right.\)