\(\frac{x^2}{\sqrt{3x-2}}-\sqrt{3x-2}=1-x\) ( ĐK : \(x>\frac{2}{3}\))
\(\Leftrightarrow\frac{x^2-3x+2}{\sqrt{3x-2}}+x-1=0\)
\(\Leftrightarrow\left(x-1\right)\left(\frac{x-2}{\sqrt{3x-2}}+1\right)=0\)
\(\Leftrightarrow x=1\)
Vậy \(S=\left\{1\right\}\)