\(\frac{x-1}{x}+\frac{1}{x+1}=\frac{2x-1}{2x^2+2}\)\(\left(x\ne0,x\ne-1\right)\)
\(\Leftrightarrow\frac{x-1}{x}+\frac{1}{x+1}-\frac{2x-1}{2\left(x^2+1\right)}=0\)
\(\Leftrightarrow\frac{\left(x-1\right)2\left(x+1\right)\left(x^2+1\right)+2x\left(x^2+1\right)-\left(2x-1\right)\left(x+1\right)x}{2x\left(x+1\right)\left(x^2+1\right)}=0\)
\(\Leftrightarrow2x^4-x^2+3x-2=0\)
Pt nghiệm vô tỉ
giải các phương trình sau
\(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x^2-2x}\)
\(\frac{2x}{2x-1}+\frac{x}{2x+1}=1+\frac{4}{\left(2x-1\right)\left(2x+1\right)}\)
\(\frac{2x-1}{3}+x=\frac{x+4}{2}\)
Giải pt:
1. x-4=2x+4
2. \(\frac{2x-1}{2}-\frac{x}{3}=x-\frac{x}{6}\)
3.\(\frac{x+3}{2x+1}-\frac{x}{x-3}=\frac{3x^2+x+9}{\left(2x+1\right)\left(x-3\right)}\)
4.\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)
Bài 1 Giải phương trình
a, \(\frac{5\left(1-2x\right)}{3}+\frac{x}{2}=\frac{3\left(x-5\right)}{4}-2\)
b, \(\left(x+2\right)^2+\left(x-1\right)\left(x+3\right)=2\left(x-4\right)\left(x+4\right)\)
c, \(\frac{3}{x-1}=\frac{3x+2}{1-x^2}-\frac{4}{x+1}\)
d, \(\frac{1}{x+1}+\frac{2x^2+1}{x^3+1}+\frac{2x^3-2x^2}{x^2-x+1}=2x\)
Bài 2 : Giải phương trình
\(x^4+3x^3+6x+4=0\)
các bạn ơi ! giúp mik với đi !! mai kiểm tra rồi
Giải các pt sau :
1/ ( 3x – 2 )( 4x +5 ) = 0
2/ 5(2x – 3) – 4( 5x -7 ) = 19 - 2( x +11)
3/ ( x2 – 2x + 1 ) – 4 = 0
4/ ( x - 1) 2 + ( x+ 3) 2 = 2 ( x -2 ) (x +1 ) + 38
5/ \(\frac{4x+3}{2}-2+3x=\frac{2x-1}{10}+\frac{19x+2}{5}-1\)
6/ \(\frac{2x+4}{5}+\frac{2x-12,4}{6}-\frac{x+3}{10}=4\)
Giúp mình với mọi người ơi !!!
Giải phương trình
2-x=3x+1
4x+7(x-2)=-9x+5
5x-2(3x-5)=7x+11
(5x+2)(x-7)=0
2x(x-5)+3(x-5)=0
\(\frac{5x-3}{6}\)=\(\frac{-2x+5}{9}\)
\(\frac{X}{3}\)-\(\frac{2x+1}{2}\)=\(\frac{5x}{6}\)
\(\frac{x}{3}\)-\(\frac{2x+1}{2}\)=\(\frac{X}{6}\)-x
\(\frac{3}{x+1}\)=\(\frac{5}{2x+2}\)
a, 12 - 3. ( x - 2 ) = ( x + 2 ).( 1 - 3x ) + 2x
b, ( x + 5 ).( x + 2 ) = 3.( 4x - 2 ) + ( x - 5 )
c, \(\frac{x-5}{x^2-5x}-\frac{x-5}{2x^2-10x}=\frac{x+25}{2x^2-50}\)
d, 4x2 - 1 = ( 2x + 1 ).( 3x - 5 )
e, x2 - 5x + 6 = 0
1. \(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
2. \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
3. \(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
\(\frac{1}{x^2+2x}+\frac{1}{x^2+6x+8}+\frac{1}{x^2+10x+24}+\frac{1}{x^2+14x+48}=\frac{4}{105}\)
Giúp mk vs
bài 1 gải phương trình
a 7x -5=13-5x
b 5(2x-3)-4(5x-7)=19-2(x+11)
c\(\frac{2x-1}{3}\)- \(\frac{5x+2}{7}\)= x+13
d \(\frac{2x-3}{3}\)-\(\frac{x-3}{6}\)=\(\frac{4}{\left(x+1\right)\left(x+3\right)}\)=1
e \(\frac{2}{x+1}\)-\(\frac{1}{x-2}\)=\(\frac{3x-11}{\left(x+1\right)\left(x+2\right)}\)
f \(\frac{3x-1}{x-1}-\frac{x-3}{6}=\frac{4x+3}{5}-17\)
