\(\frac{2x}{3x^2-x+2}-\frac{7x}{3x^2+5x+2}=1\)
\(\frac{2x}{3x^2-x+2}-\frac{7x}{3x^2+3x+2x+2}=1\)
\(\frac{2x}{3x^2-x+2}-\frac{7x}{3x\left(x+1\right)+2\left(x+1\right)}=1\)
\(\frac{2x}{3x^2-x+2}-\frac{7x}{\left(3x+2\right)\left(x+1\right)}=1\)
\(-15x^3+17x^2-10x=9x^4+12x^3+7x^2+8x+4\)
\(-15x^3+17x^2-10x-9x^4-12x^3-7x^2-8x-4=0\)
\(-27x^3+10x^2-18x-9x^4-4=0\)
=> pt vô nghiệm