\(\frac{2}{5}.x\)+40%.x-1=\(\frac{1}{2}\)
x.(\(\frac{2}{5}\)+40%)=\(\frac{3}{2}\)
x.\(\frac{4}{5}\)=\(\frac{3}{2}\)
x=\(\frac{15}{8}\)
Vậy x=\(\frac{15}{8}\)
Bài 1: Tìm x
1)\(2\left|\frac{1}{2}.x-\frac{3}{8}\right|-\frac{3}{2}=\frac{1}{4}\)
2) -5.\(\left(x+\frac{1}{5}\right)-\frac{1}{2}.\left(x-\frac{2}{3}\right)=\frac{3}{2}.x-\frac{5}{6}\)
3) 3.\(\left(x-\frac{1}{2}\right)-5.\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
4) \(\frac{3}{4}-2.\left|2.x-0,125\right|=2\)
5) \(2.\left|\frac{1}{2}.x-\frac{1}{3}\right|-\frac{3}{2}=\frac{1}{4}\)
Cần gấp giúp mình với ai trả lời mình tick cho.
Bài 1: Tìm x, biết: a) \(1\frac{1}{2}x+\frac{-4}{5}=4\) b) \(\frac{2}{3}x+\frac{-1}{2}x=\frac{-5}{12}\) c) \(\frac{3}{7}x-\frac{2}{3}x=\frac{10}{21}\)
Bài 2 : Tìm x, biết :
1) \(x-\left|1\frac{1}{6}\right|=\frac{5}{21}\)
2) \(x+\left|-1\frac{2}{3}\right|=\left|-\frac{3}{4}\right|\)
3) \(\left|x-\frac{1}{3}\right|=\frac{5}{2}\)
4) \(\left|x+\frac{2}{3}\right|=0\)
5) \(\left|x+2\right|=\frac{1}{3}-\frac{1}{5}\)
6) \(\left|x-4\right|=\frac{1}{5}-\left(\frac{1}{2}-\frac{5}{4}\right)\)
7) \(\left|x-\frac{5}{4}\right|=-\frac{1}{3}\)
Bài 1 : Tính
1) \(\frac{4}{7}-\frac{1}{14}+\left|\frac{-5}{21}\right|\)
2) \(\left|\frac{-2}{3}\right|-\frac{1}{2}+3\)
3) \(\left|\frac{7}{-4}\right|-\frac{5}{8}+\frac{-2}{3}\)
4) \(\frac{4}{5}+\left|\frac{-3}{2}\right|+\frac{1}{-4}\)
5) \(\left|\frac{-1}{4}\right|-3+\frac{3}{4}\)
6) \(\left|\frac{-1}{3}\right|-\frac{5}{4}+\frac{1}{5}\)
Bài 2 : Tìm x, biết :
1) \(x-\left|1\frac{1}{6}\right|=\frac{5}{21}\)
2) \(x+\left|-1\frac{2}{3}\right|=\left|-\frac{3}{4}\right|\)
3) \(\left|x-\frac{1}{3}\right|=\frac{5}{2}\)
4) \(\left|x+\frac{2}{3}\right|=0\)
5) \(\left|x+2\right|=\frac{1}{3}-\frac{1}{5}\)
6) \(\left|x-4\right|=\frac{1}{5}-\left(\frac{1}{2}-\frac{5}{4}\right)\)
7) \(\left|x-\frac{5}{4}\right|=-\frac{1}{3}\)
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E cần gấp lắm ạ, cảm ơn.
Bài 1 : Tính
1) \(\frac{4}{7}-\frac{1}{14}+\left|\frac{-5}{21}\right|\)
2) \(\left|\frac{-2}{3}\right|-\frac{1}{2}+3\)
3) \(\left|\frac{7}{-4}\right|-\frac{5}{8}+\frac{-2}{3}\)
4) \(\frac{4}{5}+\left|\frac{-3}{2}\right|+\frac{1}{-4}\)
5) \(\left|\frac{-1}{4}\right|-3+\frac{3}{4}\)
6) \(\left|\frac{-1}{3}\right|-\frac{5}{4}+\frac{1}{5}\)
Bài 2 : Tìm x, biết :
1) \(x-\left|1\frac{1}{6}\right|=\frac{5}{21}\)
2) \(x+\left|-1\frac{2}{3}\right|=\left|-\frac{3}{4}\right|\)
3) \(\left|x-\frac{1}{3}\right|=\frac{5}{2}\)
4) \(\left|x+\frac{2}{3}\right|=0\)
5) \(\left|x+2\right|=\frac{1}{3}-\frac{1}{5}\)
6) \(\left|x-4\right|=\frac{1}{5}-\left(\frac{1}{2}-\frac{5}{4}\right)\)
7) \(\left|x-\frac{5}{4}\right|=-\frac{1}{3}\)
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E đang cần gấp, cảm ơn :)
1.cho góc xoy = 50 độ .Biết x'oy' là góc đối của góc xoy ,khi đó x'oy' có số đo là
a.130 độ b.50 độ c.40 độ d.kết quả khác
2.cho 2 đường thẳng xx' và yy' cắt nhau tại O sao cho xoy = \(\frac{2}{3}\) xoy' số đo góc của xoy' là
a.56 độ b.72 độ c.18 độ d.108 độ
3.thực hiện phép tính
\(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
4.tìm x biết
\(\left|x-\frac{4}{5}\right|=\frac{1}{2}\)
5.cho a =\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right).....\left(\frac{1}{100^2}\right)\) so sánh a với \(\frac{-1}{2}\)
1. Tìm x, biết:
a) \(\frac{2}{5}x-x=\frac{\left(-2018\right)^0}{5^2}\)
b) \(\left|-1\frac{1}{2}x+2x\right|-\frac{7}{4}=0,5\)
c) x + \(\left(x+\frac{2}{7}\right)+\frac{-5}{11}=\frac{4}{11}\)
d) |0,25x - 20o/o| \(+\frac{3}{8}=1\frac{3}{8}\)
\(\frac{12}{16}=\frac{-x}{4}=\frac{21}{y}=\frac{z}{80}\) \((-0,6x-\frac{1}{2}).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)
\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
\(\left(2x-3\right).\left(6-2x\right)=0\)
\(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
\(2|\frac{1}{2}x-\frac{1}{3}|-\frac{3}{2}=\frac{1}{4}\)
\(\frac{3}{4}-2|2x-\frac{2}{3}|=2\)
Tìm x
a) 2x-\(\frac{2}{3}\)-7x = \(\frac{3}{2}\)-1
b) \(\frac{3}{2}\)x-\(\frac{2}{5}\)=\(\frac{1}{3}\)x - \(\frac{1}{4}\)
c)\(\frac{2}{3}\) - \(\frac{5}{3}\)x = \(\frac{7}{10}\)x +\(\frac{5}{6}\)
d) 2x -\(\frac{1}{4}\)= \(\frac{5}{6}\) - \(\frac{1}{2}\)x
e) 3x -\(\frac{5}{3}\)= x-\(\frac{1}{4}\)
Giúp mk với mn người ơiiii
