Ta có \(\frac{2}{3}\)x-\(\frac{1}{2}\)x=\(\frac{5}{2}\)
x*(\(\frac{2}{3}\)-\(\frac{1}{2}\))=\(\frac{5}{2}\)
x*\(\frac{1}{6}\)=\(\frac{5}{2}\)
x=\(\frac{5}{2}\):\(\frac{1}{6}\)
x=15
2/3 x - 1/2 x = 5/2
(2/3 - 1/2) x = 5/2
1/6 x = 5/2
x = 5/2 : 1/6
x = 15
Vậy x = 15
\(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{2}\)
\(x.\left(\frac{2}{3}-\frac{1}{2}\right)=\frac{5}{2}\)
\(x.\left(\frac{1}{6}\right)=\frac{5}{2}\)
\(x=\frac{5}{2}:\frac{1}{6}\)
\(x=15\)
Vậy x=15
x.(\(\frac{2}{3}\)-\(\frac{1}{2}\))= \(\frac{5}{2}\)
x.\(\frac{1}{6}\)=\(\frac{5}{2}\)
x=\(\frac{5.6}{2}\)
x=15
\(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{2}\)
\(\left(\frac{2}{3}-\frac{1}{2}\right)-x=\frac{5}{2}\)
\(\frac{1}{6}-x=\frac{5}{2}\)
\(x=\frac{1}{6}-\frac{5}{2}\)
\(x=\frac{-7}{3}\)
\(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{2}\)
\(\left(\frac{2}{3}-\frac{1}{2}\right)x=\frac{5}{2}\)
\(\left(\frac{4}{6}-\frac{3}{6}\right)x=\frac{5}{2}\)
\(\frac{1}{6}x=\frac{5}{2}\)
\(x=\frac{5}{2}:\frac{1}{6}\)
x=15
2/3.x-1/2.x=5/2
x.(2/3-1/2)=5/2
x.1/6=5/2
x=5/2:1/6
x=5/2.6/1
x=15
(2/3-1/2).x=5/2
(4/6-3/6).x=5/2
1/6.x=5/2
x=5/2:1/6
x=5/2.6
x=30/2
x=15