Question

\(\frac{1}{\sqrt{x-\sqrt{2x+1}}}\)

tìm đkxđ

\(\frac{1}{\sqrt{x-\sqrt{2x+1}}}\)

Answer 1

ĐKXĐ: \(\left\{{}\begin{matrix}2x+1\ge0\\x-\sqrt{2x+1}>0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\ge-\frac{1}{2}\\x\ge0\\x^2>2x+1\end{matrix}\right.\) \(\Rightarrow x>1+\sqrt{2}\)