4FeS2 + 11O2 => 2 Fe2O3 + 8SO2
SO2 +Ba(OH)2=> BaSO3 + H2O
0,15 mol<=0,15 mol
2SO2 +Ba(OH)2 => Ba(HSO3)2
x mol=>0,5x mol=>0,5x mol
mBa(OH)2=85,5 gam=>nBa(OH)2=0,5 mol
nBaSO3=0,15 mol
=>x=0,7 mol
tổng nSO2=0,7+0,15=0,85 mol =>nFeS2=0,425 mol=>m=0,425.120=51 gam
mdd X=0,7.64+200-32,55=212,25 gam
mBa(HSO3)2=0,5.0,7.299=104,65 gam
C% dd X=104,65/212,25.100%=49,31%