\(n_{_{ }Al}=\dfrac{67.5}{27}=2.5\left(mol\right)\)
\(4Al+3O_2\underrightarrow{t^0}2Al_2O_3\)
\(2.5....1.875\)
\(V_{O_2}=1.875\cdot22.4=42\left(l\right)\)
\(V_{kk}=5V_{_{ }O_2_{ }}=5\cdot42=210\left(l\right)\)
PTHH: \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
Ta có: \(n_{Al}=\dfrac{67,5}{27}=2,5\left(mol\right)\) \(\Rightarrow n_{O_2}=1,875\left(mol\right)\)
\(\Rightarrow V_{O_2}=1,875\cdot22,4=42\left(l\right)\) \(\Rightarrow V_{kk}=5\cdot V_{O_2}=5\cdot42=210\left(l\right)\)
a) PTHH: \(4Al+3O_2\rightarrow2Al_2O_3\)
Ta có: \(n_{Al}=\dfrac{67,5}{27}=2,5\left(mol\right)\)
Theo PTHH: \(n_{O_2}=\dfrac{3}{4}n_{Al}=\dfrac{3}{4}.2,5=1,875\left(mol\right)\)
=> \(V_{O_2\left(đktc\right)}=1,875.22,4=42\left(l\right)\)
b) \(V_{kk}=42.5=210\left(l\right)\)
