Bổ sung: Khí O2 được đo ở ĐKTC.
\(n_{Fe}=\dfrac{m_{Fe}}{M_{Fe}}=\dfrac{11,2}{56}=0,2\left(mol\right)\)
PTHH: \(3Fe+2O_2\underrightarrow{t^o}Fe_3O_4\)
...........3.............2............1........
...........0,2..........0,4/3.......0,2/3......
a. \(V=V_{O_2\left(ĐKTC\right)}=n_{O_2}\cdot22,4=\dfrac{0,4}{3}\cdot22,4\approx2,99\left(l\right)\)
b. \(m=m_{Fe_3O_4}=n_{Fe_3O_4}\cdot M_{Fe_3O_4}=\dfrac{0,2}{3}\cdot232\approx15,47\left(g\right)\)
a)
4P+5O2to→2P2O54P+5O2→to2P2O5
Sản phẩm : Điphotpho pentaoxit.
b)
PTHH: 3Fe +2O2 →Fe3O4
\(+n_{Fe}=\dfrac{11,2}{56}=0,2\left(mol\right)\)
Theo PTHH ta có:
\(+n_{O_2}=\dfrac{2}{3}n_{Fe}=\dfrac{2}{15}\left(mol\right)\)
\(+n_{Fe3O4}=\dfrac{1}{2}n_{Fe}=0,1\left(mol\right)\)
\(+V_{O2}=\dfrac{2}{15}.22,4=2,98\left(lit\right)\)
\(+m_{Fe2O3}=0,1.160=16\left(gam\right)\)
