Có 1344ml = 1,344l
=> \(n_{O_2}=\frac{1,344}{22,4}=0,06\left(mol\right)\)
PTHH: 4Fe + 3O2 --> 2Fe2O3
a -> 0,75a (mol)
2Mg + O2 --> 2MgO
b --> 0,5b (mol)
=>\(\left\{{}\begin{matrix}56a+24b=4,32\\0,75a+0,5b=0,06\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}a=0,072\left(mol\right)\\b=0,012\left(mol\right)\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}m_{Fe}=0,072.56=4,032\left(g\right)\\m_{Mg}=0,012.24=0,288\left(g\right)\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}\%Fe=\frac{4,032}{4,32}.100\%=93,33\%\\\%Mg=\frac{0,288}{4,32}.100\%=6,67\%\end{matrix}\right.\)
MIK NGHĨ ZẬY!!!
