\(n_{O_2}=\dfrac{1.904}{22.4}=0.085\left(mol\right)\)
Bảo toàn O :
\(n_{CO_2}=n_{H_2O}=\dfrac{1.62+\dfrac{1.904}{22.4}\cdot32}{44+18}=0.07\left(mol\right)\)
\(n_{este}=\dfrac{0.07\cdot2+0.07-0.085\cdot2}{2}=0.02\left(mol\right)\)
\(M=\dfrac{1.62}{0.02}=81\)
\(CT:C_3H_6O_2,C_4H_8O_2\)