\(n_{CO_2}=n_{CaCO_3}=\dfrac{4.5}{100}=0.045\left(mol\right)\)
\(CT:C_nH_{2n}O_2\)
\(m_O=0.99-0.045\cdot12-0.045\cdot2=0.36\left(g\right)\)
\(n_O=\dfrac{0.36}{16}=0.0225\left(mol\right)\)
\(n_{este}=0.01125\left(mol\right)\)
\(n=\dfrac{0.045}{0.01125}=4\)
\(CT:CH_3COOC_2H_5,C_2H_5COOCH_3\)