Điều kiện: \(x\ne-2,1,1\)
Từ pt trên ta có: \(\dfrac{3x-1}{x-2}-4=\dfrac{x-7}{x-1}-\dfrac{2x-1}{x+1}\)
<=>\(\dfrac{-x-9}{x+2}=\dfrac{-x^2-3x-8}{x^2-1}\)
<=>\(\left(-x-9\right)\left(x^2-1\right)=\left(x+2\right)\left(-x^2-3x-8\right)\)
<=> 4x2 -15x - 25=0 <=>\(\left[{}\begin{matrix}x=5\\x=\dfrac{-5}{4}\end{matrix}\right.\left(nhân\right)\)