Ta có :
\(\dfrac{-x}{27}=\dfrac{-3}{x}\Rightarrow-x\cdot x=-3\cdot27\Rightarrow-\left(-x\right)^2=-81\)
\(\Rightarrow x=9\veebar-9\)
-x/27=-3/x
<=>-(x)2=-81
<=>x2=81<=>x=9
Bài 2:Tìm x biết:
a)\(\dfrac{1}{7}+x=\dfrac{-2}{3}\)
b)\(\dfrac{-2}{3}:x=\dfrac{-5}{6}\)
c)\(\left\{\dfrac{3}{5}-2x\right\}.\dfrac{5}{8}=1\)
d)\(\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}\)
e)\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
f)\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
g)\(\left|X+\dfrac{1}{3}\right|-4=\dfrac{-1}{2}\)
h)\(\left(\dfrac{1}{32}\right)^x.8^{2x}=512\)
i)\(5,3x+\left(-3,3\right)x+1,7=-4,9\)
tìm x
a,\(\dfrac{6}{7}-\dfrac{3}{4}x=-1\dfrac{1}{2}x-3\)
b\(\left(4x-1\right)^2=\left(4x-1\right)^4\)
c\(\left(\dfrac{4}{5}-\dfrac{3}{4}:x\right)^3=\dfrac{-1}{27}\)
d\(\left|\dfrac{4}{3}-\dfrac{1}{4}x\right|:2\dfrac{1}{3}=0,5\)
giúp mình nhé
TÌm x biết
a) \(1+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+....+\dfrac{1}{x\left(x+1\right):2}=1\dfrac{2019}{2021}\)
Tìm x biết: (x-\(\dfrac{2}{3}\))\(^2\)=\(\dfrac{5}{6}\)
tìm x
\(\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}\)
\(2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}\)
\(\left(\dfrac{5}{6}x-0,3\right):2\dfrac{1}{3}=25\%\)
\(\dfrac{4}{7}-\dfrac{2}{3}x=1,5+\dfrac{4}{5}x\)
GIÚP MÌNH NHÉ
Tìm x :
\(\dfrac{2}{5}.\left(1-\dfrac{1}{2}x\right)-2x=\dfrac{1}{5}\)
Tìm số nguyên x và y
a) \(\dfrac{x}{2} +\dfrac{y}{3} = \dfrac{x+y}{2+3}\)
b) \(\dfrac{x}{3} - \dfrac{4}{y} = \dfrac{1}{5}\)
TÌM X
A,\(\dfrac{3}{7}x-2\dfrac{1}{3}=0,5\)
b,\(\dfrac{4}{7}-\dfrac{2}{3}:x=1\dfrac{1}{4}\)
C,\(\left(\dfrac{2}{3}x+2\dfrac{1}{4}\right):3\dfrac{1}{5}=0,75\)
D,\(\left|\dfrac{4}{5}-\dfrac{2}{3}x\right|:\dfrac{1}{4}-\dfrac{2}{3}=1\)
GIÚP MÌNH NHÉ
\(\dfrac{2}{3}x-\dfrac{3}{2}\left(x-\dfrac{1}{2}\right)=\dfrac{5}{12}\)
