H2SO4 + 2NaOH → Na2SO4 + 2H2O
\(m_{H_2SO_4}=50\times19,6\%=9,8\left(g\right)\)
\(\Rightarrow n_{H_2SO_4}=\dfrac{9,8}{98}=0,1\left(mol\right)\)
a) Theo PT: \(n_{NaOH}=2n_{H_2SO_4}=2\times0,1=0,2\left(mol\right)\)
\(\Rightarrow m_{NaOH}=0,2\times40=8\left(g\right)\)
\(\Rightarrow C\%_{ddNaOH}=\dfrac{8}{25}\times100\%=32\%\)
b) Theo PT: \(n_{Na_2SO_4}=n_{H_2SO_4}=0,1\left(mol\right)\)
\(\Rightarrow m_{Na_2SO_4}=0,1\times142=14,2\left(g\right)\)
\(\Sigma m_{dd}=50+25=75\left(g\right)\)
\(\Rightarrow C\%_{ddNa_2SO_4}=\dfrac{14,2}{75}\times100\%=18,93\%\)