\(H2SO4+Na2CO3\rightarrow Na2SO4+H2O+CO2\)
b) \(n_{H2SO4}=\frac{9,8}{98}=0,1\left(mol\right)\)
\(n_{Na2SO4}=n_{H2SO4}=0,1\left(mol\right)\)
\(m_{Na2SO4}=0,1.142=14,2\left(g\right)\)
c) \(n_{CO2}=n_{H2SO4}=0,1\left(mol\right)\)
\(m_{CO2}=0,1.44=4,4\left(g\right)\)
\(m_{dd}sau-pư=9,8+100-4,4=105,4\left(g\right)\)
\(C\%_{Na2SO4}=\frac{14,2}{105,4}.100\%=13,47\%\)