Question

để trung hòa 150ml dung dịch H2SO4 1M cần bao nhiêu gam dung dịch NaOH 10%

Answer 1

\(n_{H_2SO_4}=0,15.1=0,15\left(mol\right)\)

PTHH: \(H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O\)

________0,15------->0,3_________________________(mol)

=> \(m_{NaOH}=0,3.40=12\left(g\right)\)

=> \(m_{ddNaOH}=\dfrac{12.100}{10}=120\left(g\right)\)

Answer 2

n_H2SO4=1.0,15=0,15(mol)

2NaOH + H₂SO_{4 \(\rightarrow\)} Na₂SO₄ + 2H₂O

   0,3   \(\leftarrow\)   0.15                                       (mol)

=> m_NaOH= 0,3.40= 12(g)

=> m_{dung dịch NaOH 10%}= \(\dfrac{12.100\%}{10\%}\)= 120(g)

 

Answer 3