\(m_{HI\left(tt\right)}=\dfrac{25.6\cdot100}{45}=\dfrac{512}{9}\left(g\right)\)
\(n_{HI}=\dfrac{\dfrac{512}{9}}{128}=\dfrac{4}{9}\left(mol\right)\)
\(H_2+I_2\rightarrow2HI\)
\(\dfrac{2}{9}...\dfrac{2}{9}......\dfrac{4}{9}\)
\(V_{H_2}=\dfrac{2}{9}\cdot22.4=4.98\left(l\right)\)
\(m_{I_2}=\dfrac{2}{9}\cdot254=56.44\left(g\right)\)
