CuO+H2--->Cu+H2O
x______x____x
Fe2O3+3H2--->2Fe+3H2O
y_______3y____2y
Hệ pt:
\(\left\{{}\begin{matrix}80x+160y=16\\64x+112y=12\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,1\\y=0,05\end{matrix}\right.\)
mCu=0,1.64=6,4(g)
mFe=0,05.2.56=5,6(g)
mCuO=0,1.80=8(g)
=>%mCuO=8/16.100%=50%
=>%mFe2O3=100%-50%=50%