Bổ sung đề : Tìm x
\(\left(-x+3\right)\left(2x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}-x+3=0\\2x+4=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}-x=-3\\2x=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{3;-2\right\}\)
(-x+3).(2x+4)=0
=>\(\left[{}\begin{matrix}-x+3=0\\2x+4=0\end{matrix}\right.\\ \left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
\(\left(-x+3\right)\left(2x+4\right)=0\Leftrightarrow\left[{}\begin{matrix}-x+3=0\\2x+4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Vậy x=3 hoặc x=-2
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)