Question

Cộng các phân thức: \(\frac{2}{X-3}\)+\(\frac{2x}{X^2-4x+3}+\frac{x}{X-1}\)

Answer 1

\(x^2-4x+3\) =\(x^2-x-3x+3\) =\(\left(x-1\right)\left(x-3\right)\)

Answer 2

https://i.imgur.com/i6GngSH.jpg

Answer 3

\(\frac{2}{x-3}\)+\(\frac{2x}{\left(x-1\right)\left(x-3\right)}\)+\(\frac{x}{x-1}\)

=\(\frac{2\left(x-1\right)}{\left(x-3\right)\left(x-1\right)}\)+\(\frac{2x}{\left(x-1\right)\left(x-3\right)}\)+\(\frac{x\left(x-3\right)}{\left(x-1\right)\left(x-3\right)}\)

=\(\frac{2x-2+2x+x^2-3x}{\left(x-1\right)\left(x-3\right)}\)

=\(\frac{x-2+x^2}{\left(x-1\right)\left(x-3\right)}\)