\(A=\left(7+7^2+7^3+7^4\right)+\left(7^5+7^6+7^7+7^8\right)+...+\left(7^{4k-3}+7^{4k-2}+7^{4k-1}+7^{4k}\right)\)
\(A=\left(7+7^2+7^3+7^4\right)+7^4\left(7+7^2+7^3+7^4\right)+7^{4k-4}\left(7+7^2+7^3+7^4\right)\)
\(A=\left(7+7^2+7^3+7^4\right)\left(1+7+7^4+7^8+...+7^{4k-4}\right)\)
\(A=7\left(1+7+49+343\right)\left(1+7^4+7^8+...+7^{4k-4}=7.400.M\right)\)
vậy \(A⋮400\)
chứng minh biểu thức \(A=75\left(4^{1975}+4^{1974}+...+4^2+5\right)+25\) chia hết cho 4^1976
Giải các phương trình sau :
a, \(6x^2-5x+3=2x-3x\left(3-2x\right)\)
b,\(\dfrac{2\left(x-4\right)}{4}-\dfrac{3+2x}{10}=x+\dfrac{1-x}{5}\)
c,\(\dfrac{2x}{3}+\dfrac{3x-5}{4}=\dfrac{3\left(2x-1\right)}{2}-\dfrac{7}{6}\)
d,\(\dfrac{6x+5}{2}-\dfrac{10x+3}{4}=2x+\dfrac{2x+1}{2}\)
e,\(\left(x-4\right)\left(x+4\right)-2\left(3x-2\right)=\left(x-4\right)^2\)
Bài 3:
a) \(\dfrac{2x-1}{5}\)-\(\dfrac{x-2}{3}\)
=\(\dfrac{x+7}{15}\)
b) \(\dfrac{x+3}{2}\)-\(\dfrac{x-1}{3}\)
=\(\dfrac{x+5}{6}\)+1
c) \(\dfrac{2\left(x+5\right)}{3}\)+\(\dfrac{x+12}{2}\)
-\(\dfrac{5\left(x-2\right)}{6}\)=\(\dfrac{x}{3}\)+11
d) \(\dfrac{x-4}{5}\)+\(\dfrac{3x-2}{10}\)-x
=\(\dfrac{2x-5}{3}\)-\(\dfrac{7x+2}{6}\)
e) \(\dfrac{\left(2x-3\right)\left(2x+3\right)}{8}\)
=\(\dfrac{\left(x-4^{ }\right)^2}{6}\)+\(\dfrac{\left(x-2\right)^2}{3}\)
d) \(\dfrac{7x^2-14x-5}{15}\)
=\(\dfrac{\left(2x+1\right)^2}{5}\)-\(\dfrac{\left(x-1\right)^2}{3}\)
e) \(\dfrac{\left(7x+1\right)\left(x-2\right)}{10}\)+\(\dfrac{2}{5}\)
=\(\dfrac{\left(x-2\right)^2}{5}\)+\(\dfrac{\left(x-1\right)\left(x-3\right)}{2}\)
a) 3(2-x)+1=4-2x
b) 2(x+4)=3-x
c) 7-3x=x-5
d) 5x-(x-1)=7
giả phương trình
\(\dfrac{x+1}{2}+\dfrac{3x-2}{3}=\dfrac{x-7}{12}\)
b) \(\dfrac{2x}{x-3}-\dfrac{5}{x+3}=\dfrac{x^2+21}{x^2-9}\)
c) x3+2x = 0
d) ( x-4) (7x-3) -x2+16=0
e) 2x-4=2
g) (x+2)(x-3) = 0
h) \(\dfrac{2}{x+1}-\dfrac{1}{x-2}=\dfrac{3x-11}{\left(x+1\right).\left(x-2\right)}
\dfrac{ }{ }\)
i) \(\dfrac{1}{x+2}+\dfrac{5}{x-2}=\dfrac{2x-12}{x^2-4}\)
Giải các pt sau:
a)\(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
b)\(\frac{201-x}{99}+\frac{203-x}{97}=\frac{205-x}{95}+3=0\)
c)\(x^3+x^2+x+1=0\)
d)(x-1)x(x+1)(x+2)=24
e)\(\left(5x-3\right)^2-\left(4x-7\right)^2=0\)
f)\(3x^2+2x-1=0\)
g)\(x^2+6x-16=0\)
h)\(x^2+3x-10=0\)
i)\(x^2+x-2=0\)
k)\(3x^2+7x+2=0\)
l)\(4x^2-12x+5=0\)
Cho hai phương trình :
\(x^2-5x+6=0\) (1)
\(x+\left(x-2\right)\left(2x+1\right)=2\) (2)
a) Chứng minh rằng hai phương trình có nghiệm chung là \(x=2\)
b) Chứng minh rằng \(x=3\) là nghiệm của (1) nhưng không là nghiệm của (2)
c) Hai phương trình đã cho có tương đương với nhau không ? Vì sao ?
giải phương trình :
1) -2(x - 3) + 5x (x - 1) = 5x (x + 1)
2) 7 - (2x + 4) = -(x + 4)
x+1/4-x-7/3=1
