Ta có :
\(\dfrac{BH}{CH}=\dfrac{9}{16}=\dfrac{BH}{9}=\dfrac{CH}{16}=\dfrac{BH+CH}{9+16}=\dfrac{10}{25}=\dfrac{2}{5}\)
\(\left\{{}\begin{matrix}\dfrac{BH}{9}=\dfrac{2}{5}\Rightarrow BH=3,6cm\\\dfrac{CH}{16}=\dfrac{2}{5}\Rightarrow CH=6,4cm\end{matrix}\right.\)
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Ta có: \(\dfrac{BH}{CH}=\dfrac{9}{16}\Rightarrow BH=CH.\dfrac{9}{16}\)
Mà \(BH+HC=BC\Rightarrow\dfrac{9}{16}HC+HC=10\)
\(\Rightarrow\dfrac{25}{16}HC=10\Rightarrow HC=6,4\left(cm\right)\)
\(\Leftrightarrow BH=3,6\left(cm\right)\)
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