ΔCAH ~ Δ CBK => CK/CH = BK/AH => CK.AH = BK.CH
=> CK^2.AH^2 = BK^2.BC^2/4 (CH = BC/2)
=> (BC^2 - BK^2).AH^2 = BK^2.BC^2/4 ( CK^2 = BC^2 - BK^2)
chia 2 vế cho :AH^2.BK^2.BC^2 được:
1/BK^2 - 1/BC^2 = 1/(4AH^2)
=> 1/BK^2 = 1/BC^2 + 1/(4AH^2)
Nguồn: vn.answers.yahoo.com