Vì \(Al\left(III\right);SO_4\left(II\right)\)
\(\Rightarrow x=3;y=2\)
\(PTHH:2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)
Al(OH)3+3H2SO4--->Al2(SO4)3+3H2O
Vậy z=3 ,y=2
Đề sai rồi
Al(OH)y + H2SO4 -> Alx(SO4)y + H2O
x=2,y=3
Al(OH)3+3H2SO4----->Al2(SO4)3+3H2O