\(\Leftrightarrow\left\{{}\begin{matrix}x\ge0;x\ne9\\P=\left(\dfrac{\left(\sqrt{x}-3\right)^2+\left(\sqrt{x}+3\right)^2+14}{2\left(\sqrt{x}+3\right)}\right)\end{matrix}\right.\)
\(\Leftrightarrow P=\dfrac{x+16}{\sqrt{x}+3}\)
\(P-4=\dfrac{x-4\sqrt{x}+4}{\sqrt{x}+3}=\dfrac{\left(\sqrt{x}-2\right)^2}{\sqrt{x}+3}\ge0\)
\(P-4\ge0\Rightarrow P\ge4\) đẳng thức khi \(\sqrt{x}=2\Rightarrow x=4\) thỏa mãn đk \(\left\{{}\begin{matrix}x\ge0\\x\ne9\end{matrix}\right.\) => DPCM