Lời giải:
Ta biết:
$\sin ^2a+\cos ^2a=1$
$\Rightarrow \cos ^2a=1-\sin ^2a=1-(\frac{2}{3})^2=\frac{5}{9}$
$\Rightarrow \cos a=\frac{\sqrt{5}}{3}$
$\tan a=\frac{\sin a}{\cos a}=\frac{2}{3}:\frac{\sqrt{5}}{3}=\frac{2}{\sqrt{5}}$
$\cot a=\frac{1}{\tan a}=\frac{\sqrt{5}}{2}$