Bài 3:
\(1,ĐK:5x+10\ge0\Leftrightarrow x\ge-2\\ 2,=\sqrt[3]{8}=2\left(m\right)\\ 3,=\left[\dfrac{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}{\sqrt{x}+1}+\sqrt{x}\right]\cdot\dfrac{1}{x+1}\\ =\dfrac{x-\sqrt{x}+1+\sqrt{x}}{x+1}=\dfrac{x+1}{x+1}=1\)
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