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Do \(\overline{X}=\dfrac{140}{2}=7\) nên :
\(\dfrac{5\cdot2+6x+7y+9\cdot3}{2+x+y+3}=\dfrac{140}{2}=7\)
\(\dfrac{37+6x+7y}{5+x+y}=\dfrac{140}{2}\)
\(\Leftrightarrow6x+7y+37=7\cdot\left(5+x+y\right)\)
\(\Leftrightarrow6x+7y+37=35+7x+7y\)
\(\Leftrightarrow6x-7x+7y-7y=35-37\)
\(\Leftrightarrow\left(-x\right)=\left(-2\right)\)
\(\Rightarrow x=2\)
\(\Rightarrow y=13\)