PTHH:
Zn + 2HCl ---> ZnCl2 + H2
\(n_{H2}=\frac{6,72}{22,4}=0,3\left(mol\right)\)( mình làm theo đktc nhé)
Theo PTHH:
\(n_{H2}=n_{Zn}=n_{ZnCl2}=0,3\left(mol\right)\)
a, \(m_{ZnCl2}=0,3\cdot\left(65+35,5\cdot2\right)=40,8\left(g\right)\)
b,
\(a=m_{Zn}=0,3\cdot65=19,5\left(g\right)\)
a) \(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(n_{H_2}=\frac{V_{H_2}}{22,4}=\frac{6,72}{22,4}=0,3\left(mol\right)\)
Theo PTHH, ta có:
\(n_{ZnCl_2}=n_{H_2}=0,3\left(mol\right)\)
\(m_{ZnCl_2}=n_{ZnCl_2}.M_{ZnCl_2}=0,3.136=40,8\left(g\right)\)
b) Theo PTHH, ta có:
\(n_{Zn}=n_{H_2}=0,3\left(mol\right)\)
\(a=n_{Zn}.M_{Zn}=0,3.65=19,5\left(g\right)\)
Đại ca đến giúp e đâyyy
