\(n_{CuSO_4.5H_2O}\)= \(\dfrac{a}{250}\)(mol)
\(n_{CuSO_4}\) = \(n_{CuSO_4.5H_2O}\) =\(\dfrac{a}{250}\)(mol)
=> \(m_{CuSO_4}\) = \(\dfrac{a}{250}\).160 = 0,64a (g)
\(n_{H_2O}\) = 5\(n_{CuSO_4.5H_2O}\)= 0,02a ( mol)
=> \(m_{H_2O}\) = 0,02a.18 = 0.36a (g)