nZn = \(\dfrac{9,75}{65}\)= 0,15 mol(hết)
mHCl = \(\dfrac{584.30}{100}\)= 175,2 g=> nHCl = \(\dfrac{175,2}{36,5}\) = 4,8 mol(dư)
Zn + 2HCl -> ZnCl2 + H2 \(\uparrow\)
0,15--------->0,15----->0,15
V = 0,15 . 22,4 = 3,36 (l)
=>a = 0,15 . 136 = 20,4 g