Ca(OH)2 + CO2 \(\rightarrow\)CaCO3 + H2O
nCaCO3=\(\dfrac{2,5}{100}=0,025\left(mol\right)\)
Theo PTHH ta có:
nCO2=nCaCO3=0,025(mol)
VCO2=22,4.0,025=0,56(lít)
%VCO2=\(\dfrac{0,56}{8,4}.100\%=\dfrac{20}{3}\%\)
%VCO=100-\(\dfrac{20}{3}\)=\(\dfrac{280}{3}\%\)