PTHH: \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
a) Ta có: \(n_{Zn}=\frac{6,5}{65}=0,1\left(mol\right)=n_{H_2}=n_{ZnCl_2}\)
\(\Rightarrow\left\{{}\begin{matrix}m_{ZnCl_2}=0,1\cdot136=13,6\left(g\right)\\V_{H_2}=0,1\cdot22,4=2,24\left(l\right)\end{matrix}\right.\)
b) Sửa đề: "của dd H2SO4"
Theo PTHH: \(n_{H_2SO_4}=n_{Zn}=0,1mol\)
\(\Rightarrow C_{M_{H_2SO_4}}=\frac{0,1}{0,2}=0,5\left(M\right)\)