Zn+2CH3OOH---->H2+(CH3OO)2Zn
n Zn=6,5/65=0,1(mol)
n H2=n Zn=0,1(mol)
V H2=0,1.22,4=2,24(l)
n (CH3OO)2Zn=n Zn=0,1(mol)
m (CH3OO)2Zn=0,1.159=15,9(g)
\(n_{Zn}=\frac{6,5}{65}=0,1\left(mol\right)\)
\(Zn+2CH_3COOH\rightarrow\left(CH_3COO\right)_2Zn+H_2\)
0,1___________________0,1________0,1
\(m_{muoi}=0,1.\left(12+3+12+16+16\right).2+65=18,3\left(g\right)\)
\(\Rightarrow V_{H2}=0,1.22,4=2,24\left(l\right)\)