\(Cu+2H_2SO_{4\left(đặc,nóng\right)}\rightarrow CuSO_4+2H_2O+SO_2\)
\(2Fe+6H_2SO_{4\left(đặc,nóng\right)}\rightarrow Fe_2(SO_4)_3+6H_2O+3SO_2\)
Theo đề bài ta có hệ: \(\left\{{}\begin{matrix}64x+56y=6\\x+\frac{3}{2}y=\frac{2,8}{22,4}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,05\\y=0,05\end{matrix}\right.\)
\(\Rightarrow\%m_{Cu}=\frac{0,05.64}{6}.100=53,33\%\)
Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O
x-----------------------------------x
| 2Fe | + | 6H2SO4 | → | Fe2(SO4)3 | + | 6H2O | + | 3SO2 |
y-----------------------------------------------------3\2y
nSO2=2,8\22,4=0,125 mol
tacó
64x+56y=6
y+3\2y=0,125
=>x=0,05
=>y=0,05
=>mCu=0,05.64=3,2g
