\(n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\) ; \(n_{H_2SO_4}=0,5.0,1=0,05\left(mol\right)\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\uparrow\)
0,2 < 0,05 ( mol )
0,05 1/60 0,05 ( mol )
\(V_{H_2}=0,05.22,4=1,12\left(l\right)\)
\(C_{M_{Al_2\left(SO_4\right)_3}}=\dfrac{\dfrac{1}{60}}{0,1}=0,17\left(M\right)\)
`->` Chọn `A`