nFe = a(mol)
nMg = b (mol)
mhh = 24a + 56b = 5.2 (g) (1)
nH2 = 3.36/22.4 = 0.15 (mol)
Fe + 2HCl => FeCl2 + H2
Mg +2HCl => MgCl2 + H2
=> x + b = 0.15 (2)
(1) , (2)
a = 0.05
b = 0.1
mFe = 2.8 (g)
mMg = 2.4 (g)
nHCl = 2nH2 = 0.15*2 = 0.3 (mol)
CM HCl = 0.3/0.5 = 0.6 M