2CH3COOH + Mg => (CH3COO)2Mg + H2
nMg = m/M = 4.8/24 = 0.2 (mol)
Theo pt ==> nCH3COOH = 0.4 (mol)
200 ml dd CH3COOH = 0.2 (l) dd CH3COOH
CM = n/V = 0.4/0.2 = 2M
CH3COOH + NaOH => CH3COONa + H2O
200ml----------0.4 (mol)
100ml----------0.2 (mol)
=====> nNaOH = 0.2 (mol) => mNaOH = 0.2x40 = 8 (g)
==> mdd NaOH = 8x100/10 = 80 (g)