CH3COOH + NaOH => CH3COONa + H2O
500 ml dd = 0.5 l dd
mNaOH = 20x30/100 = 6 (g)
nNaOH = m/M = 6/40 = 0.15 (mol)
Theo phương trình => nCH3COOH = 0.15 (mol)
CM dd CH3COOH = n/V = 0.15/0.5 = 0.3M
2CH3COOH + Na2CO3 => 2CH3COONa + CO2 + H2O
nNa2CO3 = 0.5x0.2 = 0.1 (mol)
Theo phương trình ==> nCO2 = 0.1 (mol)
VCO2 = n x 22.4 = 0.1 x 22.4 = 2.24 (l)